#### POWER IN ROLLING - idc-online

Consider two high roll mill as shown in the figure. For one revolution of the top roll the resultant rolling load P moves along the circumference of a circle equal to 2π.a Since there are two work rolls involved, the work done is equal to Work done =2 (2.π.a).P = 4P.π.a If N is the speed of rotation of the rolls then Power = Work done/sec= 4P.π.a.N/60 Ie. Power= (4P.π.a.N/60x1000) Kw ...

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